Question

As satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth\'s surface. Find a). its speed in the orbit b). its kinetic energy. c). The potential energy of the earth satelilte system and d). its time period. Mass of the earth =6xx10^24kg.

Answer 1

Answer:

as satellite of mass 1000kg is supposed to orbits the earth at a height of 2000km above the earth \ s surface. Fins a its speed in the orbits b . the eath satellite systems and d. its time period. Mass of the earth =6×× 24

Answer 2

Here is your answer:

Explanation:

Speed of the satellite =  GM/ r+ h = gR2 / r = h

v=  9.8 x (6400 x 10^3) 2/ 10^6 x ( 6.4 + 2)

v = 9.8 x 6.4 x 6.4 x 10^6/ 8,4

v = 6.9 x 10^3 m/s = 6.9 Km/s

Kinetic energy = 1/2 mv2

= 1/2 x 1000 x (6.9 x 10^3)2

= 1/2 x 1000 x (47.6 x 1o^6)

= 2.38  x 10^10 J

Potential energy

The potential energy is given by

U= - GMm / r

 = gmR)2 / R+h

U=  - 9.8 x 1000 x (6.4 x 10^6)2/ 6.4 x 10^6 + 2 x 10^ 6

  =  4.76 x 10^6 J

 

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