Question

As shown in figure, amsses of 2 kg and 4 kg are tied to two ends of a wire passed over a pulley. Cross sectional area of wire is 2 cm². Calculate longitudinal strain produced in wire. [g = 10 m/s² and Y = 2 × 10¹¹ Pa]

Answer 1

accn of blocks= a = 20/ 6 = 10/3 m/sec^2.
For 2 kg: T - 20 = 2a => T = 2 ( 10 + a)
Stress = T / A = T/ (2/100).
Strain= Stress / Y