Question

As shown in figure the tension in the horizontal cord is 30n the weight w and the tension in the string oa in newton are ​

Answer 1

Answer:

From the figure Tsin30∘=30

Tsin30∘=30….(i)

Tcos30∘=W

Tcos30∘=W ….(ii)

By solving equations (i) and (ii), we get

W=30√3N

W=30root3N

and T=60N

Answer 2

Answer:

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