Question

As shown in the adjoining figure from a circular card sheet of radius 14 cm two circles of radius 3.5 cm and the rectangle of length and breadth of 1 cm are removed find the area of the remaining portion of the seed take Pi is equal to 22 upon 7​

Answer 1

Area of the circular card = πr² = 22/7 × 14 × 14

= 616 cm²

Area of removed part = 2 × area of circles + area of rectangle

= 2 × 22/7 × 3.5 × 3.5 + 1 × 1

= 77 + 1

= 78 cm²

Area of remaining part = Area of circular card - Area of removed part

= 616-78

= 538 cm²

Hope this helps you...

Answer 2

$\large{\bf{\red{\underline{\underline{AnsWer}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$