Question

As shown in the figure a particle is released from highest poms
smooth path. The distance of point of strike from A will be
(1) 10 m
(2) 5 m
(3) 20 m
(4) none of these
5m​

Answer 1

Given:

As shown in the figure a particle is released from highest position as shown. All the surfaces are smooth.

To find:

Distance of striking point from A ?

Calculation:

First of all, we need to apply CONSERVATION OF MECHANICAL ENERGY:

∆PE = ∆KE

=> Mg(∆H) = ½ Mv²

=> g(10 - 5) = ½ × v²

=> v² = 100

=> v = √(100)

=> v = 10 m/s

From point B , the particle will follow a projectile motion (see attached diagram):

• Time to reach ground is t :

$\therefore \: t = \sqrt{ \dfrac{2h}{g} }$

$\implies \: t = \sqrt{ \dfrac{2 \times 5}{10} }$

$\implies \: t = 1 \: sec$

Now, distance from Point A (i.e. range)

$\therefore \: d = v \times t$

$\implies \: d = 10 \times 1$

$\implies \: d = 10 \: m$

So, distance of striking from point A is 10 metres.

Answer 2

answer in 3 photos. it was not taking one whole picture