as shwon in figure,LK=6√2 then 1)Mk=? 2)ML=? 3)MN=?
Answers
Given :-
- LK = 6√2 .
To Find :-
- MK = ?
- ML = ?
- MN = ?
Solution :-
In right angled ∆MLK we have,
→ cos θ = LK / MK
→ cos 30° = 6√2/ MK
→ (√3/2) = 6√2/MK
→ √3 * MK = 12√2
→ MK = (12√2/√3)
→ MK = (4 * 3 * √2)/√3
→ MK = 4 * √3 * √2
→ MK = 4√6 (Ans.)
also, In right angled ∆MLK we have,
→ tan θ = LM / LK
→ (1/√3) = LM / 6√2
→ LM = 6√2/√3
→ LM = (6√2/√3) * (√3/√3)
→ LM = (6√6/3)
→ LM = 2√6 (Ans.)
now, in right angled ∆MKN,
→ sin θ = MK / MN
→ sin 45° = 4√6/ MN
→ (1/√2) = 4√6 / MN
→ MN = 4 * √3 * √2 * √2
→ MN = 4 * 2 * √3
→ MN = 8√3 (Ans.)
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