Question

as the adjoining figure,
I seg BA I ray CE and
seg AB = seg AC
then mLA=2
B
n) 100° (2) 40° (3) 70° (4) 30°​

Answer 1

Answer:

ED =~ BC

Step-by-step explanation:

CE is angle bisects of ACB

From vertical angle bisects theorem

AE / EB = AC / BC ---(equation 1)

BD is angle bisects of ABC

From vertical angle bisects theorem,

AD/DC = AB/BC = AC/BC (Therefore AB=AC) ---2

From (1) & (2)

AE/EB = AD/DC

So, ED is parallel to BC.

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Hope it helps ❤️