Math, asked by johannajeyapal, 4 days ago

As the name suggests, please find x, it will be really helpful, will give 5 stars and thanks if your helpful, and the best gets to be the brainiest

Giving 20 points for a good answer

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Answers

Answered by lianb9062
0

Answer:

a) 2

b) 0

c) 3

d) 1

Step-by-step explanation:

a) 1/5 = 0.2 and 25/625= 0.4 --> 0.2^2 = 0.04

b) Put x as 0 and solve, you'll get 81/1 which is 81

c) 4^(2x3)/4^3 = 64, try moving variables and values around in the equation

d) Pretty simple, if x is 1 then the rest of the values stay the same, 4^3 = 64

Answered by kiran12355
0

Step-by-step explanation:

1) (25/625)=(1/5)^x

(5/25)^2=(1/5)^x

(1/5)^2=(1/5)^x

x=2

2). (81*3^x)/(3^2x)=81

81/[3^(-x)*3^(2x)]=81

81/3^x=81

3^x=3^4

x=4

3) 4^(2x)/4^x=64

4^(2x)*4^(-x)=64

4^(x)=4^3

x=3

4). (2^2x)^3=64

2^(6x)=64

2^(6x)=2^6

6x=6

x=1

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