Question

As The s-character of hybridized orbital decreases , the bond angle wiil decrease , increase , does not change or becomes zero ?

Answer 1

As s character increases the bond angle increases.

Answer 2

Answer:

Concept:

In valence bond theory, orbital interbreeding (or hybridization) is the concept of combining atomic orbitals to generate new hybrid electron density (with different energies, shapes, and other properties than the constituent atomic orbitals) suited for electron pairing to form chemical bonds. For example, a carbon atom's valence-shell s orbital interacts with three valence-shell p orbitals to produce four equivalent sp3 mixes in a tetrahedral arrangement around the carbon to connect to four additional atoms. Hybrid orbitals are useful in describing molecular geometry and atomic bonding properties because they are symmetrically arranged in space. The most common way to make hybrid orbitals is to combine molecular nuclei with similar energies.

Given:

The bond angle will decrease, rise, stay the same, or become zero when the s-character of the hybridized orbital diminishes.

Find:

find the answer for the given question

Answer:

In a hybridization, the sigma type bond contributes to the s-character. The bond orientation, bond length, bond strength, and orbital size are all affected by hybridization. The bond angle increases as the s-character increases, and vice versa. This is because the electrons are positioned in such a way that they suffer the least amount of repulsion. As a result, the higher the s-character, the higher the electron density across the core atom, and therefore the electrons are organized at a greater angle to prevent repulsion and promote stability. The size of the orbitals grows as the s-character decreases, and vice versa. This is because s-orbitals are closest to the nucleus than p-orbitals, hence the lower the s-character, the higher the orbital will be. Let us now consider the question in light of these considerations. The bond angle reduces as the s-character of a hybrid orbital lowers: the bond angles for sp,sp2andsp3 hybrid orbital angular momentum are 1800,1200, and 109.50, respectively. As a result, it is correct.

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