As the seceretary of the eco-club of our school and notice 100 words requesting the students of participate in the Tree plantation program of our school. Get the notice by the headmaster.
Answers
Answer:
† Question :-
The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction.
\large \dag† Answer :-
\begin{gathered}\red\dashrightarrow\underline{\underline{\sf \green{The \: Original \: Fraction \: is \: \frac{3}{11} }} }\\\end{gathered}
⇢
The Original Fraction is
11
3
\large \dag† Step by step Explanation :-
Let Numerator and Denominator of Original Fraction be :
Numerator = x
As Per the question numerator of the fraction is 8 less than the denominator so,
Denominator should be = x + 8
So ,
\begin{gathered}\text{Original Fraction = } \frac{\text x}{\text x + 8} \\ \end{gathered}
Original Fraction =
x+8
x
❒ When 3 is added to the numerator and 3 is subtracted from the denominator :
\begin{gathered} \rm \text{Fraction Becomes } : \frac{x + 3}{x + 5} \\ \end{gathered}
Fraction Becomes :
x+5
x+3
⏩ According To Question :
\begin{gathered} \large \blue \bigstar \: \red{ \bf \frac{x + 3}{x + 5} = \frac{3}{4} } \\ \end{gathered}
★
x+5
x+3
=
4
3
\begin{gathered}:\longmapsto \rm 4(x + 3) = 3(x + 5 )\\ \end{gathered}
:⟼4(x+3)=3(x+5)
\begin{gathered}:\longmapsto \rm 4x + 12 = 3x + 15 \\ \end{gathered}
:⟼4x+12=3x+15
\begin{gathered}:\longmapsto \rm 4x - 3x = 15 - 13 \\ \end{gathered}
:⟼4x−3x=15−13
\purple{ \large :\longmapsto \underline {\boxed{{\bf x = 3} }}}:⟼
x=3
\begin{gathered}\blue\dashrightarrow\underline{\underline{\sf \orange{Numerator \: of \: Original \: Fraction = 3 }} }\\ \end{gathered}
⇢
Numerator of Original Fraction=3
☆ As numerator of the fraction is 8 less than the denominator
\begin{gathered}\rm\therefore \: Denominator = 3 + 8\\ \end{gathered}
∴Denominator=3+8
\begin{gathered}\blue\dashrightarrow\underline{\underline{\sf \orange{Denominator \: of \: Original \: Fraction = 11 }} }\\ \end{gathered}
⇢
Denominator of Original Fraction=11
Therefore,
\large\underline{\pink{\underline{\frak{\pmb{ Original \: Fraction = \dfrac{3}{11} }}}}}
Original Fraction =
11
3
Original Fraction =
11
3
Answer:
Good morning students
on _ _ _ day ther is teer plantation program
each student have to broght 1 plant
from each class we want 100 plant
I hope that from each class we well gat 100 plants
Thank you