Question

As you can see in the image properties, the resolution of the image is 1024⨉720.
It has the standard colour depth of 24 bits.
Use this information to calculate the number of bits required to represent this image.

Answer 1

Explanation:

1 Byte = 8 Bit 1 Kilobyte = 1,024 Bytes 1 Megabyte = 1,048,576 Bytes 1 Gigabyte = 1,073,741,824 Bytes

Step 1: Multiply the detectors number of horizontal pixels by the number of vertical pixels to get the total number of pixels of the detector.

Step 2: Multiply total number of pixels by the bit depth of the detector (16 bit, 14 bit etc.) to get the total number of bits of data.

Step 3: Dividing the total number of bits by 8 equals the file size in bytes.

Step 4: Divide the number of bytes by 1024 to get the file size in kilobytes. Divide by 1024 again and get the file size in megabytes.

Examples:

Perkin Elmer 1621: 2048 x 2048 = 4,194,304 (4.2 megapixel Detector)

4,194,304 pixels X 16 bit = 67,108,864 ÷ 8bits = 8,388,608 Bytes ÷1024 = 8,192 Kilobytes ÷ 1024 = 8 Megabytes

VARIAN 2520: 1,920 x 1536 = 2949120 (2.95 Megapixel Detector)

2,949,120 X 16 bit = 47185920 ÷ 8bits = 5,898,240 Bytes 5,760 Kilobytes ÷ 1024 = 5.625 Megabytes)

Answer 2

Answer:

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