Math, asked by ag111, 11 months ago

Ascending order of 6√5,7√3,8√2​

Answers

Answered by madhumitha26301
6

Answer: 8√2,7√3,6√5

Step-by-step explanation:

We should arrange the numbers according to their roots.

Answered by pinquancaro
38

The numbers in ascending order is 8\sqrt2<7\sqrt3<6\sqrt5.

Step-by-step explanation:

Given : Numbers 6\sqrt{5},\ 7\sqrt{3},\ 8\sqrt{2}

To find : Writing the numbers in ascending order ?

Solution :

To determine the order we write the numbers in simpler form by squaring them.

Numbers 6\sqrt{5},\ 7\sqrt{3},\ 8\sqrt{2} squaring the numbers,

(6\sqrt5)^2=6^2\times 5=180

(7\sqrt3)^2=7^2\times 3=147

(8\sqrt2)^2=8^2\times 2=128

Now, 128<147<180

So, 8\sqrt2<7\sqrt3<6\sqrt5

Therefore, the numbers in ascending order is 8\sqrt2<7\sqrt3<6\sqrt5

#Learn more

Arrange in ascending order 3,8,-2,16,-4,2

https://brainly.in/question/9842217

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