Ascertain bodyweight 22.4 to gram and as a measure volume of 4.7 CC the possible error in the measurement of mass and volume at 0.01 gram NCC than maximum error in the density will be
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Explanation:
m=22.42gm,Δm=0.01gm⇒
m
Δm
=
22.42
0.01
=
22.42
1
v=4.7cc,Δv=0.1cc⇒
v
Δv
=
4.7
0.1
=
4.7
1
density d=
v
m
⇒ error
d
Δd
=
m
Δm
−
v
Δv
max
m
d
Δd
∣
max
=
m
Δm
+
v
Δv
d
Δd
∣
max
×100%=(
m
Δm
+
v
Δv
)×100%
⇒
d
Δd
∣
max
×100%=
2242
1
×100%+
47
1
×100%
=2.17%
nearly 2%
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