Question

Asha dropped an object of mass 4 Kg from a height of 10m
The object has a speed of mat position and is at a height
of om above the round positions, the object is om above
the ground. At position the objectim above the ground
in D, the objectis mere picoterostometer beight)
above the Assume teile​

Answer 1

Answer:

Given :-

The object has a speed of 0 m/s at position A and is at a height

A  of 10m above the ground.

To find :-

Velocity & time taken to reach at B , C & D

Solution :-

At  t = 0    position  A  - 10 m above ground    velocity =  0

PE = mgh = 4 * 10 * 10 = 400 Joule  

KE =(1/2)mv² = 0  

At position B  - 6 m above ground distance covered  (10 - 6) = 4 m  

S = ut + (1/2)at²

u = 0  

a = g = 10  

=> 4 = (1/2)(10)t²  

=> t = √0.8  =  0.9 sec  

V = U  + at   =  9 m/s  

PE = 4 * 10 * 6 ≈ 240 joule

KE = 400 - 240 ≈ 160 Joule  

At position C  - 4 m above ground distance covered  (10 - 4) =6 m  

S = ut + (1/2)at²

u = 0  

a = g = 10  

=> 6 = (1/2)(10)t²  

=> t = √1.2  ≈ 1.1 sec  

V = U  + at   ≈  11 m/s    

PE = 4 * 10 * 4 = 160 joule  

KE = 400 - 160 = 240 Joule  

At position D  - 0 m above ground distance covered  (10 - 0) =10 m  

S = ut + (1/2)at²    

u = 0  

a = g = 10  

=> 10 = (1/2)(10)t²  

=> t = √2  = 1.4sec  

V = U  + at   =  14 m/s  

PE = 4 * 10 * 0 =  0 joule  

KE = 400  Joule  

Position  Distance from ground  PE    KE     Time         Velocity        

A                   10 m                        400   0        0  s             0 m/s  

B                   6 m                          240  160     0.9 s           9 m/s  

C                   4 m                          160   240     1.1 s            11 m/s  

D                   0 m                          0       400    1.4 s           14 m/s

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