Asha is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 25m, 12 and 8m respectively. From each can of paint 200m ^ 2 of area is painted. How many cans of paint will she need to paint the room?
Answers
Given,
Dimensions of the cuboidal hall;
length, l = 25 metres
breadth, b = 12 metres
height, h = 8 metres
The total area painted using each can of paint = 200 m^2
To find,
The number of cans of paint needed to paint the entire hall.
Solution,
This mathematical problem can be solved by using the simple formulae of mensuration, as follows,
Total area to be painted
= 2 x (area of the floor) + 2 x (area of a smaller wall) + 2 x (area of a bigger wall)
= 2 x lb + 2 x lh + 2 x bh
= 2 x (lb + lh + bh)
= 2 x ( 25x12 + 25x8 + 12x8 )
= 2 x (596) m^2
= 1192 m^2
So total number of cans needed
= total area to be painted ÷ area painted using each can of paint
= (1192 ÷ 200)
= 5.96, i.e., 6 cans approximately.
Hence, 6 cans of paint are needed to paint the entire hall.