Question

Asha's age is 2 more than the square of nisha'a age.wen nisha grows to asha's present age,asha's age would be 1 year less than 10 times nisha's present age. Find their ages​

Answer 1

$according \: \: to \: \: question \\ let \: \: nishas \: \: age \: \: be \: \: x \\ ashas \: \: age \: is \: \: \: \: \: \: \: \: {x}^{2} + 2 \\ \\ when \: \: nishas \: \: age \: \: {x}^{2} + 2 \\ ashas \: \: age \: \: 10( {x}^{2} + 2) - 1 \\ = 10 {x}^{2} + 19$

Answer 2

Answer:

Asha's age is 27yrs and Nisha's age is 5 yrs.

Step-by-step explanation:

Let, Nisha's present age be x yrs. .... (i)

Then, Asha's persent age will be (x²+2) yrs. ... (iii)

ATQ, when Nisha's age will be (x²+2) yrs. .... (ii)

Then, Asha's age would be (10x-1) yrs. .... (iv)

Therefore, (ii) - (i) = (iv) - (iii)

Because, the years will be equal during the age growth.

→ x²+2-x = 10x-1-x²-2

→ x²+x²-x-10x+2+2+1 = 0

→ 2x²-11x+5 = 0

→ 2x²-10x-x+5 = 0

→ 2x(x-5) -1(x-5) = 0

→ (2x-1) (x-5) = 0

→ 2x-1 = 0 or → x-5 = 0

→ x = 1/2 or 5

Since, age is never a fraction, so x should be 5yrs.

→ x = 5 yrs.

→ x²+2 = (5)²+2 = 25+2

= 27 yrs.

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