Ashell is fired from a gun from the bottom of a hill along its slope. the slope of the hill is and the angle of barrel to the horizontal is = 60o, the initial velocity of the shell is 21 m/s. if the distance from the gun to the point at which the shell strikes the plane is = k meters then find k/10.
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Initial velocity of shell, u=21 m/s
Slope of the hill=α=30°
Angle of the barrel to the horizontal,
β=60°
θ=β−α=60°−30°=30°
Distance of point from the gun at which shell will fall=Maximum range
R=2u^2/g×sinθ cos(θ+α)/cos^2α
=2×21^2×sin30°cos60°/9.8×cos^2 30°
=2×21×21×1/2×1/2 / 9.8×3√/2×√3/2
=30 m
Slope of the hill=α=30°
Angle of the barrel to the horizontal,
β=60°
θ=β−α=60°−30°=30°
Distance of point from the gun at which shell will fall=Maximum range
R=2u^2/g×sinθ cos(θ+α)/cos^2α
=2×21^2×sin30°cos60°/9.8×cos^2 30°
=2×21×21×1/2×1/2 / 9.8×3√/2×√3/2
=30 m
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