Question

Ashish has a clock with triangular frame its dimensions are 20 CM, 24 cm and 24 cm one of the edges of the frame is cracked Ashish puts tape along the boundary twice what is the length of the tape put around the frame​

Answer 1

Answer:

10 92929229292929 99

Step-by-step explanation:

2o2iekkeenndndndnddn

Answer 2

Given:

Ashish has a clock with triangular frame its dimensions are 20 CM, 24 cm

and 24 cm

One of the edges of the frame is cracked.

Ashish puts tape along the boundary twice.

To find :

The length of the tape put around the frame​.

Solution:

Ashish puts tape along the boundary of the clock.

The boundary of the triangular clock is equal to its perimeter.

Therefore, perimeter of a triangle = A + B + C

Where, A , B ,  C are its dimensions.

Perimeter of a triangle = 20 + 24 + 24

Perimeter of a triangle = 68 cm

The boundary of the triangular clock is 68 cm

Ashish puts tape along the boundary twice.

Then, The length of the tape put around the frame​ is 68 × 2 = 136 cm

Final answer:

The length of the tape put around the clock with triangula frame​ is 136 cm.