Ashok and mohan can do a piece of work in 12 days. Mohan and binod together do it in 15 days. If ashok is twice as good a workman as binod. In how much time will mohan alone can do the work
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Answered by
81
Thank you for asking this question, here is your answer:
Let Ashok as A and Mohan as B and Binod as C:
A + B = 12 days
B + C = 15 days
Efficiency - A/C = 2/1
A = 2u and C = 1u
Let the total work be 60u ( LCM of 12 and 15)
One day work for -
A + B = 5u - (1)
B + C = 4u - (2)
Putting the value of A=2u in eq. 1
B = 3u
Now no. of days taken by B to complete the work = 60 / 3 = 20 days
For A = 60 / 2 = 30 days
For C = 60 /1 = 60 days
If there is any confusion please leave a comment below.
Answered by
19
Answer:
Ashok and mohan can do a piece of work in 12 days. Mohan and binod together do it in 15 days. If ashok is twice as good a workman as binod. In how much time will mohan alone can do the work
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