Math, asked by flowercute288, 7 months ago

Ashok bought a second-hand car in 90000.He paid 1/6 of the price in cash and rest in 10 equal monthly instalment .Find the amount he had to pay every month​

Answers

Answered by wwwprincekumar2267
0

Answer:

6500

Step-by-step explanation:

1/6 of 90000 is 15000

remaining money = 65000 these amount of money he pay in 10 instalment so cost of one instalment is 6500

Answered by armktkc
5

Answer:

Cost of the second hand car= 90000 rupees.

Fraction of money he paid in cash=1/6

Therefore,total money he paid in cash=

90000×1/6=15000

Now,the money left=

90000-15000=75000

Money he paid in 10 equal month=

75000/10=7500

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