Ashok bought a second-hand car in 90000.He paid 1/6 of the price in cash and rest in 10 equal monthly instalment .Find the amount he had to pay every month
Answers
Answered by
0
Answer:
6500
Step-by-step explanation:
1/6 of 90000 is 15000
remaining money = 65000 these amount of money he pay in 10 instalment so cost of one instalment is 6500
Answered by
5
Answer:
Cost of the second hand car= 90000 rupees.
Fraction of money he paid in cash=1/6
Therefore,total money he paid in cash=
90000×1/6=15000
Now,the money left=
90000-15000=75000
Money he paid in 10 equal month=
75000/10=7500
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