Ashok covered a distance of 40 m due east then he turned toward north and further covered a distance of 30 m. What is the total distance
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You can solve this question easily by using vectors.
Total displacement = 40i + 30j
R = √40²+30²
R = 50m
Displacement means the shortest distance between initial and final position.
R is the resultant magnitude.
You can even use Pythagoras Theorem.
Just make a triangle and solve!
(B² + P² = H²)
B = base
H = hypotenuse
P = Perpendicular
Distance = 30m + 40m
= 70m
Distance is the total path length.
Total displacement = 40i + 30j
R = √40²+30²
R = 50m
Displacement means the shortest distance between initial and final position.
R is the resultant magnitude.
You can even use Pythagoras Theorem.
Just make a triangle and solve!
(B² + P² = H²)
B = base
H = hypotenuse
P = Perpendicular
Distance = 30m + 40m
= 70m
Distance is the total path length.
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