Question

Ashok fixed a triangular tent of height 3m. He tied the ends of the tents to two pegs fixed on the ground 8m apart. What is the length of the tent from peg to peg?

Answer 1

lenght of mid point from one peg=8/2=4
using pythagoros theorem
lenght of the tent from peg to peg=root 3 sq.+4sq.
=root 9 +16
=root 25
=5 m

Answer 2

Answer: Length of the tent from peg to peg is 10 m.

Step-by-step explanation:

Since we have given that

Height of triangular tent = 3 m

Distance between two pegs = 8 m

As shown in the figure,

In ΔABD,

BD = 8 m

BC = CD = 4 m

Since, ΔACD is right angle triangle.

$H^2=B^2+P^2\\\\H^2=3^2+4^2\\\\H^2=9+16\\\\H^2=25\\\\H=\sqrt{25}=5\ m$

So, Length of the tent from peg to peg is 5 m +5 m = 10 m.