Question

Ashok goes 30 metres north then turns right and walks 40 metres then again turns right and walks 40 metres how many metres is the away from his original position

Answer 1

Answer:

50

Step-by-step explanation:

pythagorean theorem

a^2 + b^2 = c^2

30^2 + 40^2

2500 = c^2

c = sqrt(2500)

c=50

Answer 2

Answer:

The distance away from the original position is 10√17 metres.

Step-by-step explanation:

                    40m

     B   _______________ C

          |                                |

30m   |                                |   30m

          |                                |

      A |______________ | D

                                           |   10m

                                           | E

Join points A and E

⇒ Δ ADE is a right angled triangle

⇒  AE is the hypotenuse

Therefore by pythagorus theorem, we get

   AE² = AD² + DE²

⇒ AE ² = 40² + 10²

⇒ AE ²= 1600 + 100

⇒ AE² = 1700

⇒ AE = 10√17 m

Therefore, the distance away from the original position is 10√17 metres.