Question

Ashok would reach his office 15 minutes early if he walked at 4 kmph from his house. He would reach it 45 minutes late if he walked at 3 kmph from his house. Find the distance between his house and office.​

Answer 1

Answer:

3.15 km

Step-by-step explanation:

V 1 = 4 km /h

t 1 = 8 minutes = 8 / 60 = 0.13 hours

4 = s / ( t + 0.13 )

4 t + 0.53 = s  ….. (1)

6 = s / ( t - 0.13 )

6 t - 0.78 = s    ….. (2)

6 t - 0.78 = 4 t + 0.53

6 t - 4 t = 0.53 + 0.78

2 t = 1.31

t = 0.65 hours

4 (0.65) + 0.53 = s

S = 3.15 km

Hope it helps you :)