Math, asked by nimsunset, 7 months ago

Ashraful and his brother Inzamnam contribute to the household expenses in a 3:4 ratio, Inzamam and his father
contribute to the household expenses in a 6: 7 ratio. If they spend 330,100 for repairing their home, how will the expense be shared between the father and his two sons? with explanation.

Answers

Answered by Kartikempire
1

Answer:

The Ashraful donation  = 84,888 Rupees

The Inzamnam donation = 1,13,184 Rupees

The father donation = 1,32,048 Rupees

Step-by-step explanation:

Let the Ashraful donation = 18x Rupees

Let the Inzamnam donation = 24x Rupees

Let the father donation = 28x Rupees

According to the question :-

18x + 24x +28x = 330,100

=> 46x+24x = 330,100

=> 70x = 330,100

=> x = 330,10/7

=> x = 4,716

Hence,

The Ashraful donation = 18x Rupees = 84,888 Rupees

The Inzamnam donation = 24x Rupees = 1,13,184 Rupees

The father donation = 28x Rupees = 1,32,048 Rupees

Answered by bagkakali
1

Answer:

expenses of Ashraful and bis brother is 3:4

=9:12

expenses of Inzamnsm and his father is 6:7

=12:14

so the expense of Ashraful:In zaman:father

=9:12:14

so expense of Ashraful is 9×330100/(9+12+14)

=9×330100/35=84882.86Rs

expense of Inzamnam is 12×330100/35=113177.14Rs

expense of father is

14×330100/35=132040Rs

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