Math, asked by naveensrivastav111, 10 months ago

ashu can do a piece of work in 24 days and nakul can do the same work in 12 days they worked together in 6 day and the nakul leave in how many will are so alone finish the remaining work.

Answers

Answered by Anonymous
10

Its stated that,

In 24 days Ashu can do the work.

∴ In 1 day Ashu can do = (1/24) parts of the work.

In 12 days Nakul can do the work.

∴ In 1 day Nakul can do = (1/12) parts of the work.

∴ In 1 day Ashu and Nakul together can do_

(1/12) + (1/24)

= (2+1) /24 [∴ The L.C.M. of 12 and 24 is 24.]

= 3/24

= 1/8 parts of the work.

∴ In 1 day they together can do 1/8 parts of the work.

∴ In 6 days they together can do = (6*1/8)

                                                       = 3/4 parts of the work.

∴ In 6 days they together can do 3/4 parts of the work.

So, after working for 6 days together the part of work remains_

(1-3/4)

= (4-3)/4 [The L.C.M. is 4.]

= 1/4 parts of the work.

According to the question Nakul left after working for 6 days and the remain part of work is done by Ashu.

As, we get earlier,

1/24 parts of the work can be done by Ashu in 1 day.

∴ 1 part of the work can be done by Ashu in 24 days

∴ 1/4 parts of the work can be done by Ashu in (24*1/4)

                                                                             = 6 days.

So, it will take 6 days to complete the remaining work.

Answered by hariharan11122006
3

Answer:

Its stated that,

In 24 days Ashu can do the work.

∴ In 1 day Ashu can do = (1/24) parts of the work.

In 12 days Nakul can do the work.

∴ In 1 day Nakul can do = (1/12) parts of the work.

∴ In 1 day Ashu and Nakul together can do_

(1/12) + (1/24)

= (2+1) /24 [∴ The L.C.M. of 12 and 24 is 24.]

= 3/24

= 1/8 parts of the work.

∴ In 1 day they together can do 1/8 parts of the work.

∴ In 6 days they together can do = (6*1/8)

                                                       = 3/4 parts of the work.

∴ In 6 days they together can do 3/4 parts of the work.

So, after working for 6 days together the part of work remains_

(1-3/4)

= (4-3)/4 [The L.C.M. is 4.]

= 1/4 parts of the work.

According to the question Nakul left after working for 6 days and the remain part of work is done by Ashu.

As, we get earlier,

1/24 parts of the work can be done by Ashu in 1 day.

∴ 1 part of the work can be done by Ashu in 24 days

∴ 1/4 parts of the work can be done by Ashu in (24*1/4)

                                                                             = 6 days.

So, it will take 6 days to complete the remaining work.

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