Ashu is x years old while his mother is x2 years old fice years hence she will be three times old as Ashu. Find their ages
Answers
SOLUTION :
Given : Ashu's present age = x years
His mother Mrs Veena's present age = x² years
After 5 years,
Ashu's age will be = (x + 5) years
His mother Mrs Veena's age will be = (x² + 5) years
A.T.Q
(x² + 5) = 3(x + 5)
(x² + 5) = 3x + 15
x² - 3x -15 + 5
x² - 3x - 10 = 0
x² - 5x + 2x - 10 = 0
[By middle term splitting]
x(x - 5) + 2(x - 5)
(x + 2)(x - 5)
(x + 2) = 0 or (x - 5) = 0
x = -2 or x = 5
Since, x (age) can’t be negative, x ≠ - 2 , so x = 5.
Ashu's present age = x years = 5 years
And His mother Mrs Veena's present age = x² years = 5² = 25 years
Hence, Ashu's present age is 5 years and His mother Mrs Veena's present age is 25 years.
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Answer:
Ashu present age = x year
mother Mrs veena present age = x^2
After 5 year
Ashu age will be = (x+5)
Mrs veena age will be = (x^2+5)
(x^2+5) = 3(x+5)
(x^2+5) = 3x+15
x^2-3x-15+5
x^2-3x-10=0
x^2-(5x-2x)-10=0
x^2-5x+2x-10=0
x(x-5)+2(x-5)=0
(x-5) (x+2)=0
(x=5). (x=-2)
Ashu present age is 5
Mrs veena present age (5)^2 = 25