ashu is x years old while his mother mrs veena is x×2 years old.five years hence mrs veena will be three times old as ashu . find their present ages
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Answer:
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Given,
Ashu's age = x years
Ashu's mother's age = x² years
After 5 years,
Ashu's age = x + 5 years
Ashu's mother's age = x² + 5 years
According to the given condition,
⇒(x²+ 5) = 3(x + 5)
⇒(x²+ 5) = 3x + 15
⇒x² - 3x - 10 = 0
⇒x² - 5x + 2x - 10 = 0 [By Factorisation]
⇒x(x - 5) + 2(x - 5)
⇒(x + 2)(x - 5)
⇒(x + 2) = 0
∴x = -2
⇒(x - 5) = 0
∴x = 5
Since, x (age) can never be negative, we take x = 5.
Now,
x = 5
∴ x² = 5²
∴ Ashu is 5 years old and her mother is 25 years old.
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