Ashu is x years old while his mother mrs. veena is x2 years old. five years hence mrs. veena will be three times old as ashu. find their present age
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Present Ages
Ashu = x years
Mrs.Veena = y years = 2x years
After Five years
Thus Ashu = x + 5 years
Mrs.Veena = y + 5 years = 2x + 5 years
According to the given condition
3(2x + 5) = x + 5
6x + 15 - x - 5 = 0
5x + 10 = 0
x = -2
Ignoring the negative signs
x = 2
y = 4
Hope this helps
Ashu = x years
Mrs.Veena = y years = 2x years
After Five years
Thus Ashu = x + 5 years
Mrs.Veena = y + 5 years = 2x + 5 years
According to the given condition
3(2x + 5) = x + 5
6x + 15 - x - 5 = 0
5x + 10 = 0
x = -2
Ignoring the negative signs
x = 2
y = 4
Hope this helps
Answered by
4
SOLUTION :
Given : Ashu's present age = x years
His mother Mrs Veena's present age = x² years
After 5 years,
Ashu's age will be = (x + 5) years
His mother Mrs Veena's age will be = (x² + 5) years
A.T.Q
(x² + 5) = 3(x + 5)
(x² + 5) = 3x + 15
x² - 3x -15 + 5
x² - 3x - 10 = 0
x² - 5x + 2x - 10 = 0
[By middle term splitting]
x(x - 5) + 2(x - 5)
(x + 2)(x - 5)
(x + 2) = 0 or (x - 5) = 0
x = -2 or x = 5
Since, x (age) can’t be negative, x ≠ - 2 , so x = 5.
Ashu's present age = x years = 5 years
And His mother Mrs Veena's present age = x² years = 5² = 25 years
Hence, Ashu's present age is 5 years and His mother Mrs Veena's present age is 25 years.
HOPE THIS ANSWER WILL HELP YOU... ..
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