Math, asked by alberteinstien7118, 1 year ago

Ashu is x years old while his mother mrs. veena is x2 years old. five years hence mrs. veena will be three times old as ashu. find their present age

Answers

Answered by vineetchoubeyp0szni
3
Present Ages
Ashu = x years
Mrs.Veena = y years = 2x years

After Five years
Thus Ashu = x + 5 years
Mrs.Veena = y + 5 years = 2x + 5 years

According to the given condition
3(2x + 5) = x + 5
6x + 15 - x - 5 = 0
5x + 10 = 0
x = -2

Ignoring the negative signs
x = 2
y = 4

Hope this helps
Answered by mathsdude85
4

SOLUTION :

Given : Ashu's present age = x years  

His mother Mrs Veena's present age = x² years  

After 5 years,  

Ashu's age will be =  (x + 5) years  

His mother Mrs Veena's age will be  = (x² + 5) years  

A.T.Q

(x² + 5) = 3(x + 5)

(x² + 5) = 3x + 15

x² - 3x -15 + 5

x² - 3x - 10 = 0

x² - 5x + 2x - 10 = 0

[By middle term splitting]

x(x - 5) + 2(x - 5)

(x + 2)(x - 5)

(x + 2) = 0  or  (x - 5) = 0

x = -2  or  x = 5  

Since, x (age) can’t be negative, x ≠ - 2 , so x = 5.

Ashu's present age = x years = 5 years

And His mother Mrs Veena's present age = x² years = 5² = 25 years

Hence, Ashu's present age is 5 years and His mother Mrs Veena's present age is 25 years.

HOPE THIS ANSWER WILL HELP YOU... ..

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