Question

Ashu is x years old while his mother Mrs Veena is x² years old. Five years hence Mrs Veena will be three times old as Ashu. Find their present ages.

Answer 1

SOLUTION :

Given : Ashu's present age = x years  

His mother Mrs Veena's present age = x² years  

After 5 years,  

Ashu's age will be =  (x + 5) years  

His mother Mrs Veena's age will be  = (x² + 5) years  

A.T.Q

(x² + 5) = 3(x + 5)

(x² + 5) = 3x + 15

x² - 3x -15 + 5

x² - 3x - 10 = 0

x² - 5x + 2x - 10 = 0

[By middle term splitting]

x(x - 5) + 2(x - 5)

(x + 2)(x - 5)

(x + 2) = 0  or  (x - 5) = 0

x = -2  or  x = 5  

Since, x (age) can’t be negative, x ≠ - 2 , so x = 5.

Ashu's present age = x years = 5 years

And His mother Mrs Veena's present age = x² years = 5² = 25 years

Hence, Ashu's present age is 5 years and His mother Mrs Veena's present age is 25 years.

HOPE THIS ANSWER WILL HELP YOU... ..

Answer 2

$\huge{Hey \ Dude}$


Here is your answer


So here given that Ashu is x years old while his mother Mrs Veena is x² years old. Five years hence Mrs Veena will be three times old as Ashu.

According to the questions


Five years later, Ashu is (x + 5) years
And his mother Mrs. Veena is (x2 + 5) years
So,
x2 + 5 = 3(x + 5)

x2 + 5 = 3x + 15

x2 + 5 – 3x – 15 =0

x2 – 5x + 2x + 10 = 0

x(x – 5) + 2(x – 5) = 0

(x – 5)(x + 2) = 0

X = 5  or x = – 2

Since, the age can never be negative
Therefore, ashu’s present age is 5 years and his mother’s age is 25 years.

Hope its help you