Math, asked by advika2203, 8 months ago

Ashu leaves home and travels 12 km North and then 5 km West to reach QutubMinar, while
Sunil leaves home and travels 12 km East and then 16 km South to get to Qutub Minar. If they
wanted to take the shortest route from their homes to Qutub Minar, what distances would each of
them cover?

Answers

Answered by aishutsh358
2

Answer:

By using Pythagoras theorem,

Ashu's shortest distance=  rot over12² + 5²= 144 + 25= root over 169

13= 13 km

Sunil= distance= root over 16² + 12²= root over 256 + 144=root over400

=20= 20 km

AShu= 13km

Sunil=20km

BRAINLIEST plz

Step-by-step explanation:

Answered by iffatyusuf
0

Answer:

13 km and 20 km

Step-by-step explanation:

For ashu,

Shortest route from his home ,

By applying pythagoras theorem

h^2=b^2+p^2 (Here,h=shortest distance)

(b= 5km)

(p=12km)

therefore,h^2=5^2+12^2

h=root over (169)

Therefore,13km

For sunil,

Shortest distance =h (let)

Therefore,by pythagoras theorem,

h^2=b^2+p^2

h=(12^2+16^2)square root

Therefore,shortest distance

20km

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