Question

Ashu's mother is thrice as old as Ashu .10 years ago the age of Ashu's mother was five times age of Ashu find the ages 5 years from now​

Answer 1

Let Ashu's age be x years.

Then, Ashu's mother's age = 3x years

10 years ago,

Ashu's age = x-10

Mother's age = 3x-10

But A/Q

Mother's age = 5 times Ashu's age

3x-10 = 5(x-10)

3x-10 =5x-50

-10+50 = 5x-3x

40 = 2x

40/2 = x

$\boxed{\boxed{\sf 20 = x}}$

So, present age of Ashu = 20 years

Present age of mother =3× 20

=60

So, ages 5 years after are:

Ashu :- 20+5 =25 years

Mother :- 60+5 =65 years

Answer 2

Solution :-

Let the age of Ashu be x.

Age of Ashu's mother = 3x.

10 Years Ago :-

Age of Ashu = x - 10

Age of Ashu's mother = 3x - 10

According To Question :-

=) 3x - 10 = 5 (x - 10)

=) 3x - 10 = 5x - 50

=) 3x - 5x = -50 + 10

=) -2x = -40

=) x = -40/-2

=) x = 20

So, the present age of Ashu = 20 years ;

Present age of Ashu's mother = 3 (20) = 60 years.

5 Years later :-

Age of Ashu = 20 + 5 = 25 years ;

Age of Ashu's mother = 60 + 5 = 65 years.

Hence, 5 years from now,

The age Ashu will be 25 years ;

Age of Ashu's mother will be 65 years.