Ashwin calculated the distance between A (5, 2) and B (-4,-1) to the nearest tenth is 9.5units. Now
you find the distance between X (4, 1) and Y (-5, -2). Do you get the same answer that Ashwin got?
Why?
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Given : Ashwin calculated the distance between A (5, 2) and B (-4,-1) to the nearest tenth is 9.5units.
To Find : the distance between X (4, 1) and Y (-5, -2).
Solution:
A (5, 2) and B (-4,-1)
=> AB = √(-4 - 5)² + (-1 - 2)²
=> AB = √(-9)² + (-3)²
=> AB = √81 + 9
=> AB = √90
=> AB = 9.5
X (4, 1) and Y (-5, -2)
=> XY = √(-5 - 5)² + (-2 - 1)²
=> XY = √(-9)² + (-3)²
=>XY= √81 + 9
=> XY= √90
=> XY = 9.5
AB = XY
get the same answer that Ashwin got
Because points X & Y are mirror image of B and A across origin respectively
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