Question

Ashwin calculated the distance between A (5, 2) and B (-4,-1) to the nearest tenth is 9.5units. Now

you find the distance between X (4, 1) and Y (-5, -2). Do you get the same answer that Ashwin got?

Why?​

Answer 1

Given : Ashwin calculated the distance between A (5, 2) and B (-4,-1) to the nearest tenth is 9.5units.

To Find :  the distance between X (4, 1) and Y (-5, -2).

Solution:

A (5, 2) and B (-4,-1)

=> AB  = √(-4 - 5)² + (-1 - 2)²

=> AB = √(-9)² + (-3)²

=> AB = √81 + 9

=> AB = √90

=> AB = 9.5

  X (4, 1) and Y (-5, -2)

=> XY  = √(-5 - 5)² + (-2 - 1)²

=> XY = √(-9)² + (-3)²

=>XY= √81 + 9

=> XY= √90

=> XY = 9.5

AB = XY

get the same answer that Ashwin got

Because points X & Y are mirror image of B and A across origin respectively

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Answer 2

Get the same number that Ashwin got because point X and Y are mirror of B and A accross Origin respectively.

Step-by-step explanation:

Given that:

• Ashwin calculated the distance between A (5, 2) and B (-4,-1) to the nearest tenth is 9.5units.

To find:

• the distance between X (4, 1) and Y (-5, -2).

Solution:

A (5,2) and B (-4,-1)

$\longrightarrow \: AB = \sqrt{( - 4 - 5} {)}^{2} + ( - 1 - 2 {)}^{2}$

$\longrightarrow \: AB = \sqrt{( - 9} {)}^{2} + ( - 3 {)}^{2}$

$\longrightarrow \: AB = \sqrt{18} + 9$

$\longrightarrow \: AB = 9.8$

X (4,1) and Y (-5,-2)

$\longrightarrow \: XY = \sqrt{( - 5 - 5} {)}^{2} + ( - 2 - 1 {)}^{2}$

$\longrightarrow \: XY= √(-9)²+(-3)²$

$\longrightarrow\: XY=√18+9$

$\longrightarrow\: XY=9.8$

Since, AB = XY

Get the same number that Ashwin got because point X and Y are mirror of B and A accross Origin respectively. Ans