Question

Asia three digit number is chosen at random what is the probability that user number is a multiple of 2

Answer 1

Asia chasen three digit no.
100,101,102,103,104.....................999
a=T1=100,d=1,
Tn = a + (n-1)×d
999= 100+(n-1)×1
999-100= n-1
899+1 = n
n = 900
n(S) = 900

let event A = user no. is multiple of 2
n(A) = 900/2 =445
P(A) = n(A)/n(S)
P(A) = 445/900
P(A) = 1/2
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