Asif cycles a distance of 105 km. On the first part of his journey he cycles 60 km in 2 hours 24 minutes. On the second part of his journey he cycles 45 km at 20 km/h. Find his average speed for the whole journey.
Answers
Answer:
700/31 km/hr
Step-by-step explanation:
total distance = 105 km
1st part
distance travelled = 60 km
time taken = 2hr 24min = 2 + 24/60 = 2 + 2/5 = 12/5 hrs
2nd part
distance travelled = 45
speed = 20 km/hr
time = distance/speed
= 45/20 = 9/4
therefore, average speed = total distance/ total time taken
= 105/( 12/5 + 9/4 ) = 105/( 93/20 ) = 105 x 20 / 93
= 700/31 km/hr
Answer:
23.38 km/h
Step-by-step explanation:
Distance traveled in 1st part of his journey = 60 km
Time taken = 2 h 24 min
Distance traveled in second part of his journey = 45 km
Speed = 20 km/h
∴ Time taken = 45 km/20 km/h
= 2.25 h
= 2 h 25 min
Avg. Speed = Total Distance/Total time
= 60 km + 45 km/2h 24 min + 2h 25 min
= 105 km/4 h 49 min
= 105 km/4.49 h
= 23.38 km/h
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