Question

Asif sold two phones for 3,580 each. On the first phone his 10% and on the other phone he losses 10% find his gain or loss percent in the whole transaction. ​

Answer 1

Answer:

0%.

Step-by-step explanation:

Total cost of two phones = Rs. 7,160

SP of first phone = 3580*110/100 = Rs 3,938.

SP of second phone = 3580*90/100 = Rs. 3,222

Total SP of both phones = Rs. 7,160

Profit/loss = SP - CP = Rs.7160 - Rs.7160 = 0.

So he did not make profit or loss in the whole transaction

Answer 2

His loss % is 0.99%

Step-by-step explanation:

Case 1:

SP of phone = Rs.3580

Gain % = 10 %

$CP = \frac{SP \times 100}{(100+P\%)}$

$CP = \frac{3580 \times 100}{(100+10)}$

$CP = 3254.54$

Case 2:

SP of phone = Rs.3580

Loss % = 10 %

$CP = \frac{SP \times 100}{(100-L\%)}$

$CP = \frac{3580 \times 100}{(100-10)}$

$CP = 3977.77$

Total CP = 3977.77+3254.54=Rs.7232.31

Total SP =  3,580+ 3,580=Rs.7160

CP >SP

SO, Loss

$Loss\% = \frac{CP-SP}{CP} \times 100 \\Loss\% = \frac{7232.31-7160}{7232.31} \times 100 \\Loss\% =0.99\%$

Hence His loss % is 0.99%

#Learn more:

A man sold two washing machines for rs.9900 each. he sold one at a gain of 10% and the other at a loss of 10% . find his gain or loss % in the whole transaction

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