Asifa and Ajita are in a hurry so they are climbing down constantly moving down escalator. Asifa and Ajita take 40 and 60 steps to reach the floor respectively. While Ajita takes 3 steps, Asifa takes 1 step in the same time. Select the number that indicates the total steps each one is required to climb down if the escalator is not moving.
A) 100 B) 80 C) 40 D) 60.
Answers
If the escalator were turned off, 80 steps would he have to take to walk up
Step-by-step explanation:
Let say Total steps = Y
Let say Asifa took 40 steps in T₁ time
So escalator did Y - 40 steps in T₁ time
Let say Ajita took 60 steps in T₂ time
So escalator did Y - 60 steps in T₂ time
Speed of Asifa = 40/T₁
Speed of Ajita = 60/T₂
Speed of Ajita = 3 * Speed of Asifa
=> 3 * 40/T₁ = 60/T₂
=> 2T₂ = T₁
Escalator Speed = (Y - 40)/T₁ = (Y - 60)/T₂
putting 2T₂ = T₁
=> (Y - 40)/2T₂= (Y - 60)/T₂
Cancelling T₁ from both sides
=> (Y - 40) = 2Y - 120
=> Y = 80
If the escalator were turned off, 80 steps would have to take to walk up
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Answer:
80
Step-by-step explanation: