Question

asimatook a loan of rupees 100000 at 12% per annum compounded half yearly Si paid rupees 112360 if (1.06)2 is equal to 1.1236then find the periods which she took the loan​

Answer 1

GiveN :

• Principal, P = Rs 100000

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• Rate of interest, R = 12% per annum annum

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• Amount paid = Rs 112360

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We've to find out the time Period for which Ashima took loan.

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We know that, if we're given with the Amt. paid, we've the required formula, that is,

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$\quad \: \implies \sf \: A = P \bigg\lgroup 1 + \dfrac{R}{200} \bigg\rgroup^2$

Substituting the values :

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$\quad \: \implies \sf \:112360 = 10000 \bigg\lgroup 1 + \dfrac{22}{200} \bigg\rgroup^2$

$\quad \: \implies \sf \: \dfrac{112360}{10000} = \bigg\lgroup\dfrac{53}{50} \bigg\rgroup^{2n}$

$\quad \: \implies \sf \: \dfrac{2809}{2500} = \bigg\lgroup\dfrac{53}{50} \bigg\rgroup^{2n}$

$\quad \: \implies \sf \: \dfrac{53}{50} = \bigg\lgroup\dfrac{53}{50} \bigg\rgroup^{2n}$

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Now, Comparing the sides, we get :

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$\quad \: \implies \sf \: 2n = 2$

$\quad \: \implies \sf \: n = \dfrac{2}{2}$

$\quad \: \implies \large{ \boxed{\frak{ \blue{n = 1}}}}$

$\therefore \: { \underline{\sf {The\: time \:period\: is\: \textbf{ \textsf{ 1 \:year.}}}}}$

Answer 2

Answer:

the answer to your question is 1 year