Question

Asimple pendulum makes 30 oscillations in 60 seconds. (i) Time period of simple pendulum is 0.5 sec (ii) Frequency of simple pendulum is 0.5 Hz (iii) Time period of simple pendulum is 2 sec (iv) Frequency of simple pendulum is 2 Hz (v) Time period is the reciprocal of frequency. Which of the statements given above are correct?​

Answer 1

Explanation:

oscillations are 30 in 60 sec then frequency n time period are given by,

f= N/t = 30/60= 0.5 Hz

T=1/f = 1/0.5= 2 sec

statement 2,3,and 5 are correct

Answer 2

(ii), (iii), and (v) are the correct statements.

Given: Number of oscillation, n = 30

           time, t = 60 s

To Find: frequency of simple pendulum, f

              Time period, T.

Solution:

To calculate f and T, the formula used:

• frequency, f = number of oscillation (n) / time(t)
• f = n / t

• Frequency of a simple pendulum is defined as the number of oscillations per unit of time.
• It is measured in hertz (Hz).

• And, the time period is the reciprocal of the frequency of the simple pendulum.
• Time period, T = 1 / frequency

Applying the formula for f :

f = 30 / 60

 = 3/6

 = 1/2

 = 0.5

f = 0.5 Hz.

Applying the formula for T:

T = 1 / f

  = 1 / 0.5

  = 10 /5

  = 2

T = 2 sec

Hence the frequency of the simple pendulum is 0.5Hz and the time period is 2 sec.