Question

asin(A/2+B)=(b+c)sinA/2

Answer 1

In triangle ABC,we have AB=c, AC=b and BC=a.

Then, we have to prove that .

Now, using the sine formulae,

⇒

⇒

⇒

⇒ (using A+B+C=180°)

⇒

Now, ], therefore,

⇒

Putting C= π-A-B, we have

⇒

⇒

⇒

⇒

Hence proved.