asinA+bsinB+csinC)^2=(a^2+b^2+c^2)(sin^2A+sin^2B+sin^2C)
Answers
Answered by
3
Answer:
20is answer
Step-by-step explanation:
ssnd sjd sk sx
Answered by
2
(asinA+bsinB+cSinc)*2=(a*2+b*2+c*2)(sin*2A+sin*2B+sin*2c)
Similar questions