Math, asked by rohandulal, 3 months ago

asinA+bsinB+csinC)^2=(a^2+b^2+c^2)(sin^2A+sin^2B+sin^2C)​

Answers

Answered by mangatjasmine06
3

Answer:

20is answer

Step-by-step explanation:

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Answered by paudelmanish01
2

(asinA+bsinB+cSinc)*2=(a*2+b*2+c*2)(sin*2A+sin*2B+sin*2c)

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