Question

asinsqtheta+bcocsqthta =c then tansqtheta is​

Answer 1

Theta is written as A.

Answer:

( b - c ) / ( c - a )

Step-by-step explanation:

Using the properties of trigonometric ratios :

• sin^2 A = 1 - cos^2 A
• 1 + tan^2 A = sec^2 A

Here,

= > a sin^2 A + b cos^2 A = c

= > a( 1 - cos^2 A ) + b cos^2 A = c

= > a - a cos^2 A + b cos^2 A = c

= > a + cos^2 A( b - a ) = c

= > cos^2 A( b - a ) = c - a

= > cos^2 A = ( c - a ) / ( b - a )

= > 1 / sec^2 A = ( c - a ) / ( b - a )

= > sec^2 A = ( b - a ) / ( c - a )

= > sec^2 A - 1 = ( b - a ) / ( c - a ) - 1

= > tan^2 A = ( b - a - c + a ) / ( c - a )

= > tan^2 A = ( b - c ) / ( c - a )