Question

asinx=bcosx=2ctanx/1-tan²x and (a²-b²)²=kc²(a²+b²) ,k=___​

Answer 1

Answer:

Bro i am not even at this class seeing this question makes me wanna faint

Answer 2

Answer:

Given that:

asinx=bcosx=

1−tan

2

x

2ctanx

and (a

2

−b

2

)

2

=kc

2

(a

2

+b

2

)

To find:

k=?

Solution:

asinx=bcosx

or, tanx=

a

b

asinx=

1−tan

2

x

2ctanx

or, asinx=

1−(

a

b

)

2

2c×

a

b

or, a×

a

2

+b

2

b

=

a

2

−b

2

2abc

or,

a

2

+b

2

1

=

a

2

−b

2

2c

or, (a

2

−b

2

)=2c

a

2

+b

2

Squaring both sides we get,

or, (a

2

−b

2

)

2

=4c

2

(a

2

+b

2

)

So, value of k=4