Question

asking same question again!! ggguys plz tell!!!!As you can see this is a cubic polynomial so we need Alpha ,beta and gamma(3 of them)to find the sum and product of the zeroes.but here only 2 zeroes got verified so Here I will take alpha as 1/2 and beta as -2 but what About gamma?What value we will take for gamma?​

Answer 1

Hey mate

You copied one of the zeroes wrong -1 for 1

further

$for \\ a {x}^{3} + b {x}^{2} + cx + d = 0 \\ \alpha + \beta + \gamma = \frac{ - b}{a} \\ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{c}{a} \\ \alpha \beta \gamma = \frac{ - d}{a}$

hope it helps