Asma is 4 years older than sadia and twice as old as hira if present age of hira is x years and sum of their ages is 25 years find the age of sadia after 3 years
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A is 4 years older than B who is twice as old as C. If the total of the ages of A, B and C be 40, the how old is B?
Let the age of C = x then
Age of B = 2x
Age of A = 2x +4
A+B+C = x+2x+2x + 4 =40
i.e. 5x + 4 = 40
5x = 40–4 = 36
x = 36/5
Age of B =(36/5)2 =72/5
Age of A = (72/5) +4=92/5
Age of C = 36/5
Age of (A+B+C) = (92/5)+(72/5)+(36/5)
= 200/5 = 40
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