Aspherical ball has radius of 28 cm. Find percentage error in it's surface area
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Step-by-step explanation:
Circumference C=2πr
⇒r=
π
14
Also,
dr
dC
=2π
Area of circle A=πr
2
⇒A=
π
14
2
Also,
dr
dA
=2πr
⇒
dC
dA
=r=
pi
14
Approximate error in A is dA=(
dC
dA
)ΔC
=
π
14
100
1
=
1400
1
of A
Percentage error in A =
14
1
%
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