Question

Aspirin is melted and half of the metal liquid is used to form 11 identical cubes where is the remaining half is used to form 7 ID nikal smallest pairs ratio of sides of cube to the radius of the new small sphere is​

Answer 1

ratio of sides of cube to the radius of the new small sphere =  2/∛3

Step-by-step explanation:

Aspirin is melted

Let say Volume of Aspirin = 2V  cm³

Then Volume of 11 identical cubes = 2V/2 = V  cm³

Volume of 7 identical spheres  = 2V - V  = V   cm³

Let say side of cube = a

then Volume of 11 Cubes = 11 a³

=>   11 a³ = V

=>  a³ = V/11

Let say radius of sphere = r

then Volume of 7 Spheres = 7 * (4/3)π r³  

= 7 * (4/3)(22/7) r³  

= 88 r³ / 3

=>   88 r³ / 3 = V

=>  r³ = 3V/88

a³ / r³    = (V/11)/(3V/88)

=> a³ / r³    =8/3

=> a / r  =  2/∛3

ratio of sides of cube to the radius of the new small sphere =  2/∛3

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