Question

asquare + b square = 58 ab = 21 find the value of a+ b
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Answer 1

Answer:

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Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

$\huge\bold{Given:}$

$\huge\bold{ {a}^{2} + {b}^{2} = 58}$

$\huge\bold{ab = 21}$

$\huge\bold{To\: Find :}$

$\huge\bold{a + b}$

Here this identity is used:-

$\bold{\boxed{{(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab}}$

Now substitute values of ab and a^2+b^2

$= > {(a + b)}^{2} = 58 + 2 \times 21$

$= > {(a + b)}^{2} = 58 + 42 = 100$

$= > a + b = \sqrt{100} = 10$

Therefore,the value of a+b is 10