Question

Asquare field of side 40 m has two crossroads of width 2m through the and parallel to its length and breadth. Find the area of the crosso find the cost of repairing the crossroads at the rate of 20 per square metre.​

Answer 1

Answer:

The dimension of the square garden and the 2 cross-roads going from its middle:

Side, a = 40 m

Width = 2 m

Therefore,

Area of the square field = a² = 40² = 1600 m²

Area of the 2 crossroads running from the middle of the field = 2 * [40*2] = 160 m²

And,

Area of the common path i.e., the middle portion of the crossroads = 2 * 2 = ²

Since the area of the middle portion is common for both the roads, so we will subtract the area of the middle portion i.e., 4 m² once from the area of the 2 crossroads i.e., 160 m²

∴ The area of the crossroads will be = 160 – 4 = 156 m²

Now,

The area of the garden excluding the crossroads is given by,

= [Area of the square field] – [Area of the crossroad]

= 1600 – 156

= 1444 m²

The cost of laying the grass is given = Rs. 7 per sq. meter

Thus,the cost of laying the grass in the square garden excluding the crossroads is,

= 1444 m² * Rs. 7

= Rs. 10108

Answer 2

Answer:

• The cost of repairing the crossroads at the rate of 20 per square metre = ₹10,108.
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